2.3 Axioms of Probability
Probability law cannot be arbitrary, it must satisfy the Axioms of Probability:
Non-negativity: \(\mathbb{P}[A] \geq 0 \text{, for any } A \subseteq \Omega\)
Normalization: \(\mathbb{P}[\Omega] = 1\)
Additivity: For any disjoint sets \(\{A_1, A_2, ...\}\) \[ \mathbb{P}\left[\bigcup_{i=1}^{\infty}A_i\right]=\sum_{i=1}^{\infty}\mathbb{P}[A_i] \]
Why these three axioms?
- Axiom I (Non-negativity) ensures that probability is never negative.
- Axiom II (Normalization) ensures that probability is never greater than 1.
- Axiom III (Additivity) allows us to add probabilities when two events do not overlap. Natural extension from
naive
probability (counting
)
Example
For the case where \(\Omega = [0,1]\) and \(\mathbb{P}[E] = \int_a^b f(x) dx\) we require (Axiom I) \(f(x) \geq 0\) and (Axiom II) \(\mathbb{P}[\Omega] = \int_0^1 f(x) dx =1\). Axiom III is also satisfied due to the additivity of integration. For example, consider two (non overlapping) intervals \(E_1 = [a,b]\) and \(E_2 = [b,c]\)
\[ \mathbb{P}[E_1 \cup E_2] = \int_a^c f(x) dx\\ = \int_a^b f(x) dx + \int_b^c f(x) dx\\ = \mathbb{P}[E_1] + \mathbb[E_2] \]