Describing the problem - Tree Example

Based on the mid point of each break, we can approximate the profiles using the function \(2z\), with a slope larger than the true value of 1.

tree_pdp |>
  transform(tree_mid_point = c(0.1, 0.4, 0.8)) |>
  transform(profile_aprox = 2 * tree_mid_point)

##        x1c_tree profile tree_mid_point profile_aprox
## 1     (0,0.177]     0.2            0.1           0.2
## 2 (0.177,0.597]     0.8            0.4           0.8
## 3     (0.597,1]     1.5            0.8           1.6